The double shear test serves as a valuable method to ascertain the shear strength, or ultimate shear stress, of mild steel specimens. Employing a Universal Testing Machine (UTM), this test allows us to understand how materials respond to forces that cause them to slide relative to each other. Two main types of UTMs are utilized: the screw type and the hydraulic type, with the latter being preferred for its ease of operation.
Shear force is the load responsible for inducing relative sliding between two adjacent parts of a material. Shear strength is defined as the maximum load applied perpendicular to a fastener’s axis that the material can endure before fracturing. In the case of double shear, the load is applied in a manner that would result in the fastener being cut into three pieces, distinguishing it from the single shear, which results in two fastener pieces.
To conduct the double shear test, the following apparatus is required:
The shear strength (Tmax) of the material under double shear is determined by the formula:
Tmax=F2A (Equation 1)
Where:
The machine’s load range is set based on the expected maximum load (F), calculated from the yield stress (fy) and the factor of safety (F.S):
T=0.45fy (Equation 2)
Therefore,
Tmax=(F.S)×0.45fy (Equation 3)
F=0.9×(F.S)×fy×A (Equation 4)
The observations taken during the double shear test are tabulated for analysis.
Using Equation (1), the ultimate shear stress is calculated as F/2A.
The ultimate shear stress of the material is found to be in units of N/m^2.